The height of a ball t seconds after It is thrown upward from a height of 7 feet and with an initial velocity of 48 feet per second is f (t) = -16t^2 + 48t + 7.

(a) Verify that f" (1) = f (2). f (1) = ft f (2) = ft

(b) According to Rolle's Theorem, what must be the velocity at some time in the interval (1, 2)?

(a)f (1) ==39, f (2) =39

(b) 0 feet/seconds

Step-by-step explanation:

The height of a ball t seconds after it is thrown upward is modeled by the equation:

(a)

(b)Rolle's theorem states that any real-valued differentiable function that attains equal values at two distinct points must have at least one stationary point somewhere between them—that is, a point where the first derivative is zero.

The velocity at some time in the interval (1,2)=0 feet/second

  21.3

step-by-step explanation:

multiplying the given equation by c/sin(25°), we get

  c = 9/sin(25°) ≈ 21.2958 ≈ 21.3

we assume "c" is the length of ab, the side opposite angle c in triangle abc.

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step-by-step explanation: