Mathematics, 22.04.2020 19:29 xojade

I have the worst teacher and I need help can anyone help me :(?

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Answer from: tiffanybrown703

Graph B: Translate 6 units to the right so f(x-6)

Graph C: Translate 3 units to the left and go down 5 units so f(x+3) - 5

Graph D: Translate 7 units to the left so f(x+7)

Graph E: Translate 6 units upwards so f(x) + 6

Graph F: Translate 2 units to the right and 3 upwards so f(x-2) +3

Step-by-step explanation:

This is just function transformations or function shifts.

If you wish to move a graph, f(x), to the left, add x by the units desired so f(x+c), where c is the units to the left.

If you wish to move the graph to the right, subtract x by the units desired so f(x-c), where c is the units to the right.

To move the graph up add the desired of units to the function.

If you want to shift upwards by a certain amount of units then f(x) + c, where c is the units upwards.

If you want to shift downwards by a certain amount of units then f(x) - c, where c is the units downwards.

Answer from: Quest

The answer is lol i dont know

Answer from: Quest

Intersecting secant-tangent theorem states that if a tangent segment and a secant segment are drawn to a circle from an exterior point, then the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment.so to break it down: 1. pq acts as the tangent and ps as the secant with an intersection at p.sr = 21rp = 3x + 3pq = 4x + 4following to equation: tangent squared = the two segments multiplied by each otherso (4x + 4) ^ 2 = (3x + 3) • (21) simplifies to 16x^2 - 31x - 47 = 0 or (16x - 47)(x + 1) x = -1 or x = 47/162. pq acts as the tangent and ps as the secant with an intersection at p (again! )sr = 16rp = xpq = 15(15) ^ 2 = 16 • x225 = 16xx = 225/163. the interesting chords are proportional to each other so a ratio is possible to set up: ap dp 10 3 + x = = —— = pc pb 8 xcross multiple to get 10x = (3 + x)(8)x = 12

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