![\sqrt[]{50} = \sqrt[]{2\cdot 25} = \sqrt[]{2}\cdot \sqrt[]{25} = 5\sqrt[]{2}](/tpl/images/0618/6290/6d992.png)
![\sqrt[]{2} = 1.41](/tpl/images/0618/6290/f935d.png)
(aproximately), then ![\sqrt[]{50} = 5\cdot 1.41 = 7.07](/tpl/images/0618/6290/7587b.png)
which is 7.1 when rounded. PLEASE ANSWET ASAP! -Brainlist to right answer
Ashton estimates the square root of 50 in the f...
Mathematics, 22.04.2020 18:50 safelix1260
PLEASE ANSWET ASAP! -Brainlist to right answer
Ashton estimates the square root of 50 in the following way: √50 = 2 √25 = 2 x 5 = 10
A- Explain why his reasoning is incorrect.
B- Estimate the square root of 50 to the nearest tenth without using your calculator.
SHOW YOUR WORK
Answers: 3
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