1. What is the area of the trapezoid? The diagram is not drawn to scale. (I point)
7 cm
15 cm
m DCO
5 cm
O 60 cm?
O 85 cm
O 12 cm
O 30 cm?
mm 25

Given:

Given that one of the base of the trapezoid is b₁ = 7 cm.

The other base of the trapezoid is given by

The height of the trapezoid is h = 5 cm.

We need to determine the area of the trapezoid.

Area of the trapezoid:

The area of the trapezoid can be determined using the formula,

where b₁ and b₂ are the bases of the trapezoid and h is the height of the trapezoid.

Substituting the values, we get;

Hence, the area of the trapezoid is 60 cm²

Thus, Option a is the correct answer.

The correct answer is D) 30

Step-by-step explanation:

The formula to solve this problem is :  

substitute 5 for h, 7 for , and 5 for

= 30

sooo the answer is 30 (not 60)

I took the test and I hope this helps :)

step-by-step :

a.   we have two

lines:   y = 4-x   and  

y = 8-x^-1

given two simultaneous equations that are both to be

true, then the solution is the points where the lines cross. the intersection is

where the two equations are equal. therefore the solution that works for both

equations is when

4-x = 8-x^-1

this is where the two lines will cross and that is the

common point that satisfies both equations.

b.   4-x = 8-x^-1

  x           4-x       8-x^-1

-3           7        

8.33

-2           6         8.5

-1           5         9

  0           4        

-

  1           3        

7

  2           2        

7.5

  3           1         7.67

the table shows that none of the x values from -3 to 3 is

the solution because in no case does

4-x = 8-x^-1

to find the solution we need to rearrange the equation to

find for x:

4-x = 8-x^-1

multiply both sides with x:

4x-x^2 = 8x-1

x^2+4x-1=0

x= -4.236, 0.236

therefore there are two points that satisfies the

equation.

find y:  

x=-4.236

y = 4-x   = 4 – (-4.236)

= 8.236

y = 8-x^-1 =   .236)^-1

= 8.236

x=0.236

  y = 4-x   = 4 – (0.236) = 3.764

y = 8-x^-1 =   8-(0.236)^-1

= 3.764

thus the two lines cross at 2 points:

(-4.236, 8.236) & (0.236, 3.764)

c.   to solve

graphically the equation 4-x = 8-x^-1

we would graph both lines: y = 4-x   and   y

= 8-x^-1

the point on the graph where the lines cross is the

solution to the system of equations.

just graph the points on part b on a cartesian coordinate

system and extend the two lines.   the

solution is, as stated, the point where the two lines cross on the graph.

step-by-step explanation:

mark brainliest!