In circle K with mLJKL = 112 and
JK = 7 units find area of sector JKL.
Round to the nearest hundredth.

Given:

Given that K is the center of the circle.

The length of JK is 7 units.

The measure of ∠JKL is 112°

We need to determine the area of the sector JKL.

Area of the sector JKL:

The area of the sector JKL can be determined using the formula,

where θ = 112 and r = 7, we get;

Simplifying, we get;

Thus, the area of the sector JKL is 47.87 square units.

the balance is found at the link

step-by-step explanation:

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

eventually after a few more steps, your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x