A campground owner had 150 meters of fencing to enclose a rectangualr field adjacent to a river and also bisect that field into two equal halves. No fencing required with river. what are the dimesions of the largest area that can be enclosed

Dimension of the Rectangle : 2W - 150 by W

Step-by-step explanation:

Given

Land Size = 150 metres

This land size represents the perimeter of the land

Let P = Perimeter

So, P = 150 m

To bisect the field into two equal halves means to divide length or width of the field into two equal halves

Let L = Length of the field

Let W = Width of the field

Assuming the length of the field is to be bisected., then the campground owner is left with 0.5L (i,e half of the length)

Perimeter of a rectangle is calculated by: 2(Length + Width)

P = 2(L + W) by substitution, becomes

150 = 2(0.5L + W) open bracket

150 = L + 2W Male L the subject the formula

L = 2W - 150

The dimension of the largest area that can be enclosed id given by (L,W)

By substitution; the expression becomes

Dimension of the Rectangle : 2W - 150 by W

it's both, now can you answer my most recent question?

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