An airplane encountered a head wind during a flight between Joppetown and Jawsburgh which took 5 hours and 30 minutes. The return flight took 5 hours. If the distance from Joppetown to Jawsburgh is 2700 miles, find the airspeed of the plane (the speed of the plane in still air) and the speed of the wind, assuming both remain constant.

a) 490.91 mph

b) 540 mph

c) speed of the wind = 49.1 mph

Step-by-step explanation:

Given that flight between Joppetown and Jawsburgh took 5 hours and 30 minutes.

Time t = 5.5hours

Distance = 2700 miles

Speed = distance/ time

Speed = 2700/5.5

Speed = 490.91 mph

The return flight took 5 hours of the same distance from = 2700 miles

Speed = 2700/5 = 540 mph

speed of the wind = the difference in the two speed

speed of the wind = 450 - 490.91

speed of the wind = 49.1 mph

Speed = 540m/s

the solution is 12x-6y

answer: i guess 5 units?

step-by-step explanation: