Mathematics, 22.04.2020 01:35 kevinmarroquin6

Prove: The square of a number that is
two more than a multiple of 3 is one more
than a multiple of 3.
(3n + 2)2 = 9n2 + 12n +4
= [ ? ]n2 + ]n+ ] +1
= [ [ ]n2 + [ ]n + 1) + 1
= 1 more than a multiple of 3

Answers: 1

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Prove: The square of a number that is
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Prove: The square of a number that is two more than a multiple of 3 is one more than a multiple of 3. (3n + 2)2 = 9n2 + 12n +4 = [ ? ]n2 + ]n+ ] +1 = [ [ ]n2 + [ ]n + 1) + 1 = 1 more than a multiple of 3

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Prove: The square of a number that is
two more than a multiple of 3 is one more
than a multiple of 3.
(3n + 2)2 = 9n2 + 12n +4
= [ ? ]n2 + ]n+ ] +1
= [ [ ]n2 + [ ]n + 1) + 1
= 1 more than a multiple of 3