Find the equation of the line that is perpendicular to y = 2x + 8 and passes though the point (8, –8).

y= -1\2x-4

Step-by-step explanation:

y=mx+c

perpinicular means you flip the slop and change the sign so the slope(m) become -1\2

y=-1\2x+c

since he gives you (8,-8) meaning x=8 and y= -8

we substitute

-8=(-1\2 x 8) +c

now we isolate c

-8+4=c

c=-4

the equation will be

y= -1\2x-4