If [infinity] cn8n n = 0 is convergent, can we conclude that each of the following series is convergent? (a) [infinity] cn(−3)n n = 0 When compared to the original series, [infinity] cnxn n = 0 , we see that x = here. Since the original for that particular value of x, we know that this . (b) [infinity] cn(−8)n n = 0 When compared to the original series, [infinity] cnxn n = 0 , we see that x = here. Since the original for that particular value of x, we know that this

a) we know that this is convergent.

b) we know that this might not converge.

Step-by-step explanation:

Given the is convergent

Therefore,

(a)   The power series has radius of convergence at least as big as 8. So we definitely know it converges for all x satisfying -8<x≤8. In particular for x = -3

∴  is convergent.

(b) -8 could be right on the edge of the interval of convergence, and so might not converge

answer: the answer is one of

step-by-step explanation:   we are given to write a proper fraction where the whole is divided into an even number of equal parts less than ten, and an odd number of those parts exist.

an even number less than 10 may be one of 2, 4, 6 or 8. so, the whole may be one of these four evens.

now, an odd number of these parts must exist, so the numerator must be an odd number, one of 1, 3, 5 or 7. it cannot be 9 because then the fraction will become improper.

thus, our fraction may be one of the following

answer: what statements

step-by-step explanation if you write the statements down then i could you.