F(x)=4x
2
+2x+6 How many distinct real number zeros does f have?

It has 0 distinct real number zeros. The function does not touch the x-axis

NO real zeros for this quadratic function.

Step-by-step explanation:

We can answer this questions looking at the discriminant () associated with this quadratic function:  

Discriminant is:  

Since we get a negative answer, this means that there are NO real solutions to this quadratic function (No real zeros). The zeros are complex numbers.

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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