Find the product d^j•d^k

d^(j+k)

Step-by-step explanation:

d^j  * d^k

We know that a^b * a^c = a^(b+c)

d^(j+k)

if you explain the the question more correctly i might be able to answer this better

step-by-step explanation:

dc=6 square root of 3 and ac is 12 square root 3

c and d

step-by-step explanation:

square root of 3/2 = 18/c

cross multiply to get 18*2=√3*c

36/√3 * √3/√3 = c

c= 36*√3/3

c=12√3