Circle Z is intersected by AC←→ and CE←→. What is the measure of AE⏜? Enter your answer in the box. mAE⏜= ° Circle Z with two secants. Point A at 11 o clock, point B at 3 o clock, point D at 4 o clock, and point E at 7 o clock are on the circle. Point C at 3.30 o clock is located outside of circle. Secant A B C and secant E D C are drawn through point C. Arc B D is labeled as 26 degrees. Angle B C D is labeled as 36 degrees.

Measure of AE = 98°

Step-by-step explanation:

In the given question Circle Z is intersected by secants AC and EC at the points B and D respectively. Now by the theorem of secants and angles, m∠BCD = By putting the values of ∠BCD = 36°, mBD = 26°36° = Multiply the equation by 272° = AE - 26°mAE = 72 + 26 = 98°Therefore, measure of AE = 98° is the answer.

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length

ans789

step-by-step explanation: