Use the graph to write a liner function that relates y to x

3y = 4x + 6

Step-by-step explanation:

y-intercept: 2

Slope: (6-2)/(3-0)

4/3

y = (4/3)x + 2

3y = 4x + 6

y=4/3x+2

Step-by-step explanation:

We need to write an equation in slope intercept form, or

y=mx+b, where m is the slope, and b is the y intercept

Slope

Slope can be found using this formula:

Let's use the points (0,2) and (6,10) for (x1,y1) and (x2,y2)

So, x1 is 0, y1 is 2, x2 is 6 and y2 is 10, and we can substitute them in

This can be reduced to

Y-Intercept

The y intercept can be found on the graph. It is the point where the line intersects the y/vertical axis. It intersects at 2.

b=2

Now we can substitute the b and m in the point slope formula

y=mx+b

y=4/3x+2

the least common denominator is 40

guess at question:

a vertical line intersects the graph of g(x,y) = 0 at two points. what conclusion follows about the function f(x) implicitly defined by g(x,f(x)) = 0?

the domain of f(x) cannot include the x coordinate of any such vertical line.

informally, f(x) is not a function, and

g(x,y)=0 cannot be solved for y uniquely.

the relation r = {(x,y) such that g(x,y) = 0} is a function if

for all (a,b) ∊ r and (c,d) ∊ r, a=c implies b=d.

step-by-step explanation: