Suppose that salaries for recent graduates of one university have a mean of $26,400$ 26,400 with a standard deviation of $1200$ 1200. Using Chebyshev's Theorem, what is the minimum percentage of recent graduates who have salaries between $22,800$ 22,800 and $30,000$ 30,000? Round your answer to one decimal place.

By the Chebyshev's Theorem, the minimum percentage of recent graduates who have salaries $22,800 and $30,000 is 89%.

Step-by-step explanation:

Chebyshev's theorem states that:

At least 75% of the measures are within 2 standard deviations of the mean.

At least 89% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean = 26,400

Standard deviation = 1200

Between $22,800 and $30,000

22800 = 26400 - 3*1200

So 22800 is 3 standard deviations below the mean

30000 = 26400 + 3*1200

So 30000 is 3 standard deviations above the mean.

By the Chebyshev's Theorem, the minimum percentage of recent graduates who have salaries $22,800 and $30,000 is 89%.

step-by-step explanation:

the original amount doesn't ''re just looking for the time it takes for 1/2 of the substance to we have

(1/2) =)     take the ln   of both sides

ln (1/2)   = )   and we can write

ln(1/2) = ) lne     and lne   = 1     so we have

ln(1/2) = -.1092t     divide both sides by -.1092

t = ln(1/2)/-.1092 = about 6.347 days = about 6.3 days (rounded)

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )