Suppose you go to a company that pays 0.03 for the first day, 0.06 for the second day, 0.12 for the third day and so on. If the daily wage keeps doubling, what will your total income be for working 29 days ? Total Income = 16106127.33 Correct

The total income after 29 days is $16,106,127.33

Step-by-step explanation:

This is a geometric progression with the first element being 0.03 and the ratio is 2. So if we want to know the total income after 29 days we can use the formula for the sum of elements in a series of that kind, this is given by:

sum(29 elements) = [(first element)*(1 - r^(29))]/(1 - r)

sum(29 elements) = [0.03*(1 - 2^(29))]/(-1)

sum(29 elements) =(0.03*(-536870911))/(-1)

sum(29 elements) = -16106127.33/(-1) = 16106127.33

The total income after 29 days is $16,106,127.33

option 1 is correct.

step-by-step explanation:

y varies inversely with x and constant of variation is 4

the equation will be:

y = k/x

where k =4 so,

y = 4/x

if we put values of x of option 1 in the above equation and find values of y

y = 4/-2 => y =-2

y = 4/-1 => y = -4

y = 4/1 => y = 4

y = 4/2 => y =2

so, all the values of x and y are correct.

if we put values of x given in other options and find value of y we cannot find whole table satisfying the equation.

hence option 1 is correct.

the correct answer option is (2x-3)(2x+3).

step-by-step explanation:

we are given the following expression and we are to factorize it:

we are to find such factors that when multiplied they give a result of 36 (9 x 4 = 36) and when added they give a result of 0.

the two such factors of 36 are negative six and postive six.

factorizing the given expression to get:

therefore, the correct factorization of is (2x-3)(2x+3).