PLEASE HELP. 18 points
You design a frame to surround a rectangular photo. The width of the frame is the same on every side as shown. write a polynomial in standard form that represents the combined area of the photo in the frame. find the combined area of the photo in the frame when the width of the frame is 4 inches.

A is 4x^2+84x+440 and B=840 square inches

Step-by-step explanation:

A is 4x^2+84x+440 and B=840 square inches

The task for a is to write a polynomial in standard form that represents the combined area of the photo and the frame. First, lets start with the bottom of the picture and frame.  On the bottom, you have 2x+ 22 inches.  Then the side of the picture and frame is 2x+20 inches. Writing in polynomial form, it would be  (2x+22)(2x+20). You would get 4x^2+84x+440 since you are using the FOIL method. Now for part b, we know that the width of the frame(or x) is 4 inches. Now we plug that into the equation.  84x is 84x4. 84x4=336   x^2 is 16.   There are four of those as you can see in the equation so 16x4=64    

336+64=400 inches    Frame= 400 inches

400 inches plus the picture(440 inches) =  840 square inches.

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

mean, 40.6

step-by-step explanation: