Paul observes that AB=AC and concludes that AB abd AC must be tangent to the circle. What is wrong with pauls reasoning?

The answer should be C

Step-by-step explanation:

we know that

the triangle AOB is congruent with triangle AOC

because

AB=AC

OB=OC> the radius of the circle

The OB side is common

but

there is no additional information that allows me to calculate the OBA angle to determine if it is a right angle

therefore

the answer is the option

C.There is no indication that AB and AC are perpendicular to the radii at the points of intersection with the circle.

Thanks (4)

answer: y = -12x + 108

step-by-step explanation: do (y = m x+b) formula.

solution:

we have to construct

∠m nt ≅ ∠p qr

the steps to draw this construction are

step 1: use a compass to draw an arc from point q which intersects the side pq at point a and the side qr at point b.

step 2: draw a segment nt and use the same width of the compass to draw an arc from point n which intersects the segment nt at a point x.

step 3:

step 4: join points n and y using a straightedge.

step 3:

option (d).maintaining the same width of the compass as ab, draw an arc from point x such that it intersects the arc drawn from n in a point y.

to draw   congruent angles , 1. width of compasses while drawing two angles should be same i.e from point at which angle has to be drawn, 2.the distance between the two points where the compass intersects the two sides should be same while drawing any two congruent angles.