Robbie, has scored 120 so far this season. He has scored all of his points on 1-point extra point kicks and 3-point field goals. He has made a total of 66 kicks. How many of each kick has he made?

39 and 27

Step-by-step explanation:

GIVEN: Robbie, has scored so far this season. He has scored all of his points on -point extra point kicks and -point field goals. He has made a total of kicks.

TO FIND: How many of each kick has he made.

SOLUTION:

Lets extra point kicks made by Robbie be

points scored using extra point kick

field goal kicks made by Robbie

point scored using field goal kick

Total points scored by Robbie

Total points scored are the sum of points scored by extra point kicks and field goal kicks.

total extra point kicks

total field goal kicks

Hence Robbie made 39 and 27 kicks of extra point kick and field goal kicks respectively.

39 extra point kicks were made and 27 field goals were made.

Step-by-step explanation:

We are given the following in the question:

Let x be the 1-point extra point kicks and y be the number of field goals.

Total number of kicks = 66

Thus, we can write the equation:

Total score = 120

Thus, we can write the equation:

Solving the equation, we get,

Thus, 39 extra point kicks were made and 27 field goals were made.

the correct answer is b. negative exponential growth.

step-by-step explanation:

you can tell it's an exponential function because it decreases rapidly then levels out and never touches the x-axis.

it is negative because the y-axis decreases as the x-axis increases.

therefore it is a negative exponential growth graph.

hope i !

option c) graph of line going through 1, 4 and 3, 10

step-by-step explanation:

let y equal to margo's coin collection

let x equal to number of years

at the begining x=0, y=1 → point=(x,y)→point=(0,1)

she adds 3 coins per year, then y=1+3x

at x=1, y=1+3(1)=1+3→y=4→point=(x,y)→point=(1,4)

at x=3, y=1+3(3)=1+9→y=10→point=(x,y)→point=(3,10)

the graph of line going through (1, 4) and (3, 10), then the option c is the correct.