For the first derivative of f(theta)=2cos(theta)+cos^2(theta),
i got
f'(theta)=-2sin(t...
Mathematics, 19.10.2019 21:30 loloi83
For the first derivative of f(theta)=2cos(theta)+cos^2(theta),
i got
f'(theta)=-2sin(theta)+2cos(theta)- sin(theta)=0
after simplifying it, the book had
(-sin(+cos(theta))=0 how did they get (1+cos( the answers is prob really simple but i am stuck on it if anyone could kindly . @mathematics
Answers: 2
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