A bag contains 2 red marbles, 3 green marbles, and 4 blue marbles.
If we choose a marble, then another marble without putting the first one back in the bag, what is the probability that the first marble will be green and the second will be red?

1/12.

Step-by-step explanation:

There are a total of 9 marbles so

Prob(drawing first a green) = 3/9.

After drawing the green there are 8 marbles left in the bag, so:

Prob(drawing a red) = 2/8.

The required probability = 3/9 * 2/8

= 1/3 * 1/4

= 1/12.

the answer is c

step-by-step explanation:

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