The mean and standard deviation of a random sample of 7 baby orca whales were calculated as 430 pounds and 26.9 pounds, respectively. Assuming all conditions for inference are met, which of the following is a 90 percent confidence interval for the mean weight of all baby orca whales.

a. 26.9 ± 1.895 (430/√7 )
b. 26.9 ±1.943 (430/√7)
c. 430 ±1.440 (26.9/√7)
d. 430 ± 1.895 (26.9/√7)
e. 430 ± 1.943 (26.9/√7)

And the best option would be:

e. 430 ± 1.943 (26.9/√7)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

represent the sample mean

population mean (variable of interest)

s=26.9 represent the sample standard deviation

n=7 represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

  (1)

In order to calculate the critical value we need to find first the degrees of freedom, given by:

Since the Confidence is 0.90 or 90%, the value of and , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.05,6)".And we see that

Now we have everything in order to replace into formula (1):

And the best option would be:

e. 430 ± 1.943 (26.9/√7)

i think is g(1)=-1.

hope that i can