The stopping distance (s) of a car varies directly as the square of its speed (v). If a car traveling 20 mph requires 60 ft to stop, find the stopping distance for a car traveling 40 mph. Round to the nearest tenth.

The stopping distance for a car traveling 40 mph is 240 feet.

Step-by-step explanation:

We are given the following in the question:

The stopping distance (s) of a car varies directly as the square of its speed (v)

Removing the sign of proportionality and adding constant of proportionality, we get

where k is constant of proportionality.

Now, when s = 60 feet, v = 20 mph

Putting values, we get,

Putting value of k in the equation, we get,

We have to find the stopping distance for a car traveling 40 mph.

Thus, the stopping distance for a car traveling 40 mph is 240 feet.

answer: x= -2y

step-by-step explanation:

ruth is 6 years old

step-by-step explanation:

6 + 24 = 30,   so 6/30 = .2  

if you do 1/5 it also equals .2, so that is the answer.