Two number cubes are rolled.

What is the probability that the first lands on 2 and the second lands on a number greater than 4?

Enter you answer, as a fraction in simplified form, in the box.

1/18

Step-by-step explanation:

Assuming the die are regular 1,2,3,4,5,6

P(2) = number of 2's/ total numbers on die

      = 1/6

Roll again

Assuming the die are regular 1,2,3,4,5,6

P (numbers greater than 4) = {5,6}/total numbers on die

                                               =2/6 = 1/3

P (2, then  number greater than 4) = 1/6 * 1/3 = 1/18

1/18

Step-by-step explanation:

P(2) = 1/6

Greater than 4: 5,6

P(>4) = 2/6 = 1/3

1/6 × 1/3 = 1/18

y=−9/2x+10

step-by-step explanation:

let's solve for y.

0−9x−2y=−20

step 1: add 9x to both sides.

−9x−2y+9x=−20+9x

−2y=9x−20

step 2: divide both sides by -2.

−2y

−2

=

9x−20

−2

y=

−9

2

x+10