If Lydia buys 1/2 pound of the Breakfast Tea and 2 pounds of the Dark Roast coffee, how many 1- pound bags of Pumpkin Spice coffee can she buy?

The question is incomplete! Complete question along with answer and step by step explanation is provided below.

Question:

Lydia is at a coffee shop and knows  she can spend no more than $65

before tax. She sees this price list in  the coffee shop.

Dark Roast Coffee    $7.50

Pumpkin Spice Coffee   $10.50

Breakfast Tea   $23.50

if Lydia buys 1/2 pound of the Breakfast Tea and 2 pounds of the Dark Roast coffee, how many 1- pound bags of Pumpkin Spice coffee can she buy?

Given Information:

Shopping Budge = $65

Price of   Dark Roast Coffee = $7.50

Price of Pumpkin Spice Coffee  = $10.50

Price of  Breakfast Tea  = $23.50

Amount of Breakfast Tea required = 1/2 pound

Amount of Dark Roast coffee required = 2 pounds

Required Information:

How many 1-pound  Pumpkin Spice Coffee can she buy = ?

n = 3 bags of 1-pound Pumpkin Spice Coffee

Step-by-step explanation:

We are given that the amount of Breakfast Tea required is 1/2 pound so the cost of Breakfast Tea is

Cost of Breakfast Tea = 1/2*23.50 = $11.75

We are also given that the amount of Dark Roast coffee required is 2 pounds so the cost of Dark Roast coffee is

Cost of Dark Roast coffee = 2*7.50

Cost of Dark Roast coffee = $15

We know that total Lydia's total budget is $65

11.75 + 15 + 10.50x = 65

Where x represents the amount of Pumpkin Spice coffee required

10.50x = 65 - 11.75 - 15

10.50x = 38.75

x = 3.64 pounds

That means Lydia can buy 3.64 pounds of Pumpkin Spice coffee.

Now assuming that the Pumpkin Spice coffee is sold only in 1-pound bags then the required number of bags that Lydia can buy is

n = 3.64 pound/1-pound

n = 3.64

Since bags cannot be in fraction so

n = 3 bags

Note: we can not round off to 4 bags since that would surpass the given budged.

-4, -2, 1, 4

step-by-step explanation:

domain = x values

range = y values