ABC is a triangle.
work out angle x. give your answer to 3 significant figures.

x = 50.5°

Step-by-step explanation:

∠ BDC and ∠ BDA are adjacent and supplementary, thus

∠ BDC = 180° - 78° = 102°

Calculate ∠ BCD using the Sine rule in Δ ABC, that is

= ( cross- multiply )

9.3 × sinC = 5.6 × sin50° ( divide both sides by 9.3 )

sinC = ≈ 0.4613, thus

C = (0.4613 ) ≈ 27.5°

The sum of the 3 angles in Δ BCD = 180°, thus

x = 180° - (102 + 27.5)° = 180° - 129.5° = 50.5°

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)  

2/3

step-by-step explanation: