The parabola y=x^2-2x+4 will have a vertex of

The vertex is at (h, k) => (1, 3)

Step-by-step explanation:

Complete the square of y=x^2 - 2x + 4 to determine the coordinates of the vertex.

Note that the first two terms of y=x^2 - 2x + 4 resemble the perfect square (x - 1)^2:

y=x^2 - 2x + 4 => y= ( x^2 - 2x + 1 )+ 4 - 1, or

                            y = (x - 1)^2 + 3

Comparing this last result to the standard equation y = (x - h)^2 + k, we see that h = 1 and k = 3.  The vertex is at (h, k) => (1, 3)

solve systems of equations by graphing. a system of linear equations contains two or more equations e.g. y=0.5x+2 and y=x-2. the solution of such a system is the ordered pair that is a solution to both equations. to solve a system of linear equations graphically we graph both equations in the same coordinate system

2x + 8

step-by-step explanation: