If log(base4)x=2.5 and log(base y)125=-3/2, find the numerical value of x/y, in simplest form.

X = (2^2)^(2.5) 
x = 2^(2 * 2.5) 
x = 2^5 
x = 32 
y^(-3/2) = 125 
y^(-3) = 125^2 
y^(-3) = (5^3)^2 
y^(-3) = (5^2)^3 
y^(-3) = 25^3 
y = 25^(-1) 
y = 1/25 

x/y => 
32 / (1/25) => 
32 * 25 => 
800 is the simplest form of above