Do ya'll know how to do this? (grade 10)

Please help im stranded :(

(15 Points)

a.) (-16,0)(0,12)

b.) (-3,0)(0, 3/2)

Step-by-step explanation:

Plug it in for each.

y= 3/4x+12 (Lets plug in our x intercept of (x,0) and our y intercept of (0,y)

x-intercept

0=3/4x+12

-12        -12

-12=3/4x

-12/(3/4)=x

-16=x

SO, your x intercept is -16 which is point (-16, 0)

Now to do your y intercept in lets plug x in as 0 instead this time:

y = 3/4(0)+12

y = 12

Your y intercept is 12

Now for b its the same process of plugging 0 in for the values let

y-int=-2(0)-4y+6=0

                      -6  -6

                       -4y/-4=-6/-4 <- divide both sides by 4

                              y = 3/2 <- Simplified answer

y int = (0, 3/2)

x-int = -2x-4(0)+6 = 0

                       +6   +6

                       -2x = 6

                           x = 6/-2 <-- Divide both sides by -2

                           x = -3     <-- Simplify

x-int = (-3, 0)

step-by-step explanation:

through just a quick inspection, one can see that the graph of this cubing function starts in quadrant iii and ends in quadrant i.   when x = 0, y = 3, so the y-intercept is (0, 3).

if graphs are part of the problem statement, share them.   .

3

step-by-step explanation: