Determine the following
quadratic equations have real
roots

1) 3x² - √2x-√3

Step-by-step explanation:

√3 x² - 2x - √3 = 0

√3 x² - 3x + x - √3 = 0

√3 x(x - √3) + 1(x - √3) = 0

(x - √3 ) (√3 x + 1) = 0

x - √3 = 0 , √3 x +1 = 0

x = √3 , x = -1/√3

step by step explanation: when u removing the parentheses and combined them that would be : x+3y-x-y=2y

to be honest i don't know but i need points so