A bag contains 24 coins. Some of these are 10 cent coins and all of the others are 5 cent coins.
iii) A second bag also contains 24 coins. in this bag the number of 5 cent coins ix x and all of the others are 10 cent coins?
iv) the total value of the coins in the second bag is 30 cents more than the total value of the coins in the first bag. Use this infomation to form an equation in x and hence find x?

Step-by-step explanation:

i don't know rnerjarhdycsayhd

what is all that apply?

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.