Please answer this question I will litterally lick ya butt if ya do

9 seconds

Step-by-step explanation:

h(t) = -16 t^2 + 1296  

Since 1296 is the initial height

We want to find when it will hit the ground or when h(t) =0

0 = -16 t^2 + 1296

Subtract 1296 from each side

-1296 = -16t^2

Divide each side by -16

-1296/-16 = t^2

81 = t^2

Take the square root of each side

sqrt(81) = sqrt(t^2)

±9 = t

Since time cannot be negative

t= 9 seconds

The initial height is 1296ft.

h(t) = -16t^2 + 1296

Solve for t.

0 = -16t^2 + 1296

~Subtract 1296 to both sides

0 - 1296 = -16t^2 + 1296 - 1296

~Simplify

-1296 = -16t^2

~Divide -16 to both sides

-1296/-16 = -16t^2/-16

~Simplify

81 = t^2

~Take the square root of both sides

√81 = √t^2

~Simplify

9 = t

Therefore, it will take the brick 9 seconds to reach the ground.

Best of Luck!

hope it

step-by-step explanation:

x^(1/6) · x^(1/6) · x^(1/6)   ·x^(1/6) = x^(4/6)   since we add the exponents

4/6 can be simplified to 2/3

the simplified form is x^(2/3)