PLZ HELP ASAP
Find f(x) if it is known that f(x−3)=0.2x−0.6.

f(x) = 0.2x

Step-by-step explanation:

hello :

let : f(x) = ax+b    calculate a  and b

f(x-3) =a(x-3)+b = ax+b-3a(*)

given    :  f(x-3) = 0.2x-0.6...(**)

by (*) and(**) :  a= 0.2    and   b-3a = - 0.6

b-3(0.2) = - 0.6

so : b=0

conclusion : f(x) = 0.2x

5 pm

step-by-step explanation:

δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)