(Photo attached) Trig question. Thanks in advance! :)

  tan(α+β) ≈ 5.8498

Step-by-step explanation:

tan(α+β) = tan(arccos(0.637) +arcsin(0.498)) = tan(50.4315° +29.8677°)

  = tan(80.2993°) ≈ 5.8498

Comment on this working

You may be expected to use trig identities to find ...

  tan(α) = √(1-cos²(α))/cos(α)

  tan(β) = sin(β)/√(1-sin²(β))

  tan(α+β) = (tan(α)+tan(β))/(1 -tan(α)tan(β))

Or

  sin(α) = √(1-cos²(α))

  cos(β) = √(1 -sin²(β))

  tan(α+β) = sin(α+β)/cos(α+b)

     = (sin(α)cos(β) +cos(α)sin(β))/(cos(α)cos(β) -sin(α)sin(β))

Either way, a calculator is definitely involved. Since a calculator is required for the solution, it is far easier to do the problem using inverse trig functions.

answer: 9

step-by-step explanation:

answer: true

step-by-step explanation: