A game involves selecting a card from a regular 52-card deck and tossing a coin. The coin is a fair coin and is equally likely to land on heads or tails.

• If the card is a face card, and the coin lands on Heads, you win $5

• If the card is a face card, and the coin lands on Tails, you win $2

• If the card is not a face card, you lose $2, no matter what the coin shows.

Find the expected value for this game (expected net gain or loss). (Round your answer to two decimal places.)

Expect to lose about $0.73 or 73 cents for each game played

Step-by-step explanation:

Let's define the four events:

F = event of drawing a face card

N = event of drawing a non-face card

H = event of the coin landing on heads

T = event of the coin landing on tails

The events F and N are complementary and this means that one event or the other, but not both, must happen. We either draw a face card (F) or we don't (N). This is why the probabilities add to 1

P(F) + P(N) = 1

Thus;

P(N) = 1 - P(F)

There are 4 suits with 3 face cards per suit (King, Queen, Jack).

So 4 x 3 = 12 face cards out of 52 cards total.

Therefore,

P(F) = probability of drawing a face card = (number of face cards)/(number of cards total)

P(F) = 12/52 = 3/13

And,

P(N) = probability of drawing a non-face card

P(N) = 1 - P(F)

P(N) = 1 - (3/13)

P(N) = 10/13

Now, assuming we have a fair coin with either side is likely to be landed on, it means that;

P(H) = 1/2

P(T) = 1/2

So, P(H) + P(T) = 1

Assuming the events of drawing a card and flipping a coin are independent, then we can form the compound probabilities

P(F & H) = P(F) x P(H)

P(F & H) = (3/13) x (1/2) = 3/26

P(F & T) = P(F) x P(T)

P(F & T) = (3/13)*(1/2) = 3/26

Now, Similar to the probability P(X) notation, let's introduce the function V(X) where V is the net value and X is the general event. To be more specific, writing V(F) represents the net value of drawing a face card.

The three cases we're concerned with are:

V(F & H) = net value for getting face card and heads = 5

V(F & T) = net value for getting face card and tails = 2

V(N) = net value for getting non face card = -2

The negative value (-2) indicates a loss of 2 dollars.

When we play the game out, there are three cases:

Case A = drawing a face card and the coin landing on heads

Case B = drawing a face card and the coin landing on tails

Case C = drawing a non-face card

What we do is multiply the probabilities for each case happening with the net values for each case.

Thus;

For case A, we have the probability P(F & H) = 3/26 and the net value V(F & H) = 5

Hence;

P(F & H) x V(F & H) = (3/26) x 5 = 15/26 = 15/26

Similarly for case B

P(F & T) x V(F & T) = (3/26) x 2 = 6/26 = 3/13

and finally case C

P(N) x V(N) = (10/13) x (-2) = -20/13

Let's now add them up to get;

(15/26) + (3/13) + (-20/13)

This gives; (15 + 6 - 40)/26 = -19/26 = $-0.73

At this expected value, it means that we expect to lose about $0.73 or 73 cents for each game played. This is not a fair game (because expected value isn't 0). Thus, the game clearly favors the house instead of the player.

13.33%

say 50 oranges, then 100 apples

80 are red, 20 are yellow

total fruit = 150

20chances out of 150 for yellow

20/150 = 13.33%

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet