What is the slope of the line that passes through the points (3, 8) and (8, 13) ?(

The slope of the line would be 1

Step-by-step explanation:

To do this, you would take the slope formula, (Y2-Y1)/(X2-X1)

Next we would plug in the points of the line

(13-8)/(8-3)

5/5

1/1

Therefore, the slope of the line is 1.

y=mx+b

step-by-step explanation:

m slope, b y-intercept

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)