Write an equation of the line that passes through the point (2, 3) and is perpendicular to the line x = -1.

A) y = 1
B) y = 3
C) y = 0
D) y = -3

B) y = 3

Step-by-step explanation:

x = -1 is a vertical line.  We want a line that is perpendicular, so it must be a horizontal line.  Horizontal lines are in the form y=  

The point it goes through is (2,3) so it goes through the y coordinate y=3

Therefore the line must be y=3

y = 3

Step-by-step explanation:

x = -1 is a vertical line.

Perpendicular to it, would be a horizontal line which has an equation of the form:

y = c

Since it passes through (2,3), c = 3

Hence the equation is:

y = 3

(x, y)→(x − 8, y − 7)

step-by-step explanation:

enjoy!

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°