A box contains 2 red marbles, 3 green marbles, and 3 blue marbles.
If we choose a marble, then another marble without putting the first one back in the box, what is the
probability that the first marble will be green and the second will be blue?
How many

9/56

Step-by-step explanation:

the odds of the first one being green is 3/8

the odds of the second one being blue is 3/7 because one was removed

multiply these to find the probability

3/8*3/7=9/56

x = ± 6i

step-by-step explanation:

x^2 = -36

take the square root of each side

sqrt(x^2) = sqrt(-36)

we know sqrt(ab) = sqrt(a) sqrt(b)

x = ±sqrt(36) sqrt(-1)

we know that sqrt (-1) = i

x = ± 6i

let's solve your equation step-by-step.

24−3x=−27

step 1: simplify both sides of the equation.

24−3x=−27

24+−3x=−27

−3x+24=−27

step 2: subtract 24 from both sides.

−3x+24−24=−27−24

−3x=−51

step 3: divide both sides by -3.

−3x

−3

=

−51

−3

x=17

answer:

x=17

step-by-step explanation:

mark brainliest and have a great day!