The sum of three numbers is 45. The second of the three numbers is three more than twice the first number, x. The third number
is two more than the first number, x. Which equation can be used to solve for the first number, x?
OOO
x + 5x + x + 2 = 45
x + x + 3 + x + 2 = 45
x + 3x + 2 + x + 2 = 45
x + 2x + 3 + x + 2 = 45

The first no. is = x

let the second no. be y .

y= 2x+3

let the 3rd no. be z

z= x+2

Therefore, x+y+z= 45

=> x+2x+3+x+2=45

Option D

it is b)

hope this : )

step-by-step explanation:

5x + 5

step-by-step explanation:

you should always add the diagrams and graphs we cannot see. this particular question is kind of borderline because we can make a graph for you.

(f + g)x = -x^2 +3x + 5 + x^2 + 2x

(f + g)x = 5x + 5

the graph of z = 5x + 5 is shown below. always use desmos when in doubt.