Suppose the diameter at breat height (in.) of tress of a certain tpye is normally distributed with μ = 8.8 and σ = 2.8, as suggested in the article "Simulating a Harvester-forwarder Softwood THinning" (Forest Products J., May 1007: 36-41). a. What is the probability that the diameter of a randomly selected tree will be at least 10in.? Will exceed 10in.? b. What is the probability that the diameter of a randomly selected tree will exceed 20in? c. What is the probability that the diameter of a randomly selected tree will be between 5 and 10in.? d. What value c is such that the interval (8.8 − c, 8.8 + c) includes 98% of all diameter values? 3 e. If four trees are independently selected, what is the probability that at least one has a diameter that exceeds 10in.?

-22

times both sides by 2, times () by 8, add alile terms, move terms, add alike and caculate divide both sides by 3

la parábola es el lugar

geométrico en el cual los puntos tienen una distancia idéntica, equidistantes,

de un punto denominado foco, f, y una recta denominada directriz

el radio vector de una

parábola es el segmento que existe entre un punto cualquiera y el foco.

por la ecuación se observa

que la parábola abre hacia la derecha, por lo cual podemos usar las siguientes fórmulas

la ecuación ordinaria de la

parábola es y^2 = 4px, donde p es la longitud desde el vértice de la parábola al

foco.

la fórmula de la directriz

es x + p = 0

resolviendo:

y^2-9x = 0

y^2 = 9x

4p = 9, entonces p = 9/4

entonces el foco tendrá la

coordenada f(9/4,0)

la directriz vendrá

expresada por

x + p = 0

x = -p

x = -9/4

el problema indica que la

ordenada es igual a 6, entonces

(6)^2=9x

x = 36/9

x = 4

entonces el punto al cual

hay que obtener la distancia será p(4,6)

calculando se tendrá: pf = 

pf = 6,25 u

ver más en -

step-by-step explanation:

the answer is 1 becuz if it were 1.0 that would rip apart the entire so ya. : )

~potato.

copyright potato 2019.