In lecture, we proved that any tree with n vertices must have n − 1 edges. Here, you will prove the converse of this statement. From now on, you can use this converse in the same way as you use statements from lecture. Prove that if G = (V, E) is a connected graph such that |E| = |V | − 1, then G is a tree.

its the second choice.

step-by-step explanation:

the elements in the range will be 7 less than the elements in the domain.

hello from mrbilldoesmath!

answer:   x^2 + y^2 = 1024

discussion:

the equation of a circle with center (h,k) and radius "r" is

(x-h)^2 + (y-k)^2 = r^2.

in our case

(x-0)^2 + (y-0) ^2 = 32^2 = 1024

you,

mrb

if you're trying to figure out how much each ounce cost it would be 0.20

cents each ounce

step-by-step explanation:

6