QUESTION 5 Write the equation for the graphed function. Graph of an abolute value function shifted 2 units to the left. f(x) = |x| – 2 f(x) = |x – 2| f(x) = |x| + 2 f(x) = |x + 2|

Acompound inequality is graphed, and its graph consists of all real numbers. which open scentence could have resulted in this solution set r> 3 or r< -2. r< 3 or r< -2. r> 3 or r> -2. r< 3 or r> -2 plz asap