Show that there does not exist any real number c such that the following function f(x) would be a valid probability density function: f(x) = ( c=(1 + x); if x > 0 0; otherwise: Repeat if f(x) were given by: f(x) = ( c=(x); if x > 0 0; otherwise: Hint: To be a valid density function f must be non-negative and integrate to 1.

the answer i think is a)

step-by-step explanation:

i used to know how to do this in 7th but i forget easily

step-by-step explanation:

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.

2.56 is the width of the garden

step-by-step explanation: