Which of the following could be the lengths of the sides of a 30°-60°-90° triangle?
B. 3V3,3V3,6
C. 13,3, 2013
D. 3,4,5

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2

there are many, many solutions to this problem.

here are 5 examples:

7555531, 7+5+5+5+5+3+1 = 31

7155553, 7+1+5+5+5+5+3 = 31

7735531, 7+7+3+5+5+3+1 = 31

7375531, 7+3+7+5+5+3+1 = 31

7335931, 7+3+3+5+9+3+1 = 31