Suppose h(t) = -0.2t? + 2t models the height, in feet, of a ball that is kicked into the air where t is
given as time, in seconds.
After how many seconds does the ball reach its maximum height?
seconds
What is the maximum height of the ball?
After how many seconds does the ball reach the ground?
seconds

Below in BOLD.

Step-by-step explanation:

h(t) = -0.2t^2 + 2t

We can find the maximum height and the time by converting to vertex form:

h(t) = -0.2(t^2 - 2t)

= -0.2[(t - 1)^2 - 1)

= -0.2(t - 1)^2 + 0.2

The time to get to maximum height = 1 second and the maximum height is 0.2 m.

When the ball reaches the ground h = 0 so

-0.2(t - 1)^2 + 0.2 = 0

(t - 1)^2 =  -0.2 / -0.2 = 1

t - 1 = 1

t = 2 seconds.

all but the second one

step-by-step explanation:

cuz that one goes over 180

mark brainliest

the ratio of grapes to blueberries she should use is 12: 3

step-by-step explanation:

if mandie is making 15 cups of fruit salad, the ratio of grapes to blueberries she should use is 12: 3.