Mathematics, 16.04.2020 17:25 tyreert1720
HURRRY TIMDE LIMIT Tasha used the pattern in the table to find the value of 4 Superscript negative 4. Powers of 4 Value 4 squared 16 4 Superscript 1 4 4 Superscript 0 1 4 Superscript negative 1 One-fourth 4 Superscript negative 2 StartFraction 1 Over 16 EndFraction She used these steps. Step 1 Find a pattern in the table. The pattern is to divide the previous value by 4 when the exponent decreases by 1. Step 2 Find the value of 4 Superscript negative 3. 4 Superscript negative 3 = StartFraction 1 Over 16 EndFraction divided by 4 = StartFraction 1 Over 16 EndFraction times one-fourth = StartFraction 1 Over 64 EndFraction Step 3 Find the value of 4 Superscript negative 4. 4 Superscript negative 4 = StartFraction 1 Over 64 EndFraction divided by 4 = StartFraction 1 Over 64 EndFraction times one-fourth = StartFraction 1 Over 256 EndFraction Step 4 Rewrite the value for 4 Superscript negative 4. StartFraction 1 Over 256 EndFraction = negative StartFraction 1 Over 4 Superscript negative 4 EndFraction In which step did Tasha make the first error? Step 1 Step 2 Step 3 Step 4
Answers: 1
Mathematics, 21.06.2019 16:10, dhernandez081
To find the extreme values of a function f(x. y) on a curve x-x(t), y y(t), treat f as a function of the single variable t and use the chain rule to find where df/dt is zero. in any other single-variable case, the extreme values of f are then found among the values at the critical points (points where df/dt is zero or fails to exist), and endpoints of the parameter domain. find the absolute maximum and minimum values of the following function on the given curves. use the parametric equations x=2cos t, y 2 sin t functions: curves: i) the semicircle x4,y20 i) the quarter circle x2+y-4, x20, y20 b, g(x, y)=xy
Answers: 2
Mathematics, 22.06.2019 00:30, tremainecrump1466
Anew test for ra is being developed. the test is administered to 750 patients with ra and 750 without ra. for the sake of the question, assume the prevalence of ra in this population is 50%. of the 750 patients with ra, 575 have a positive result. of the 750 patients without ra, 150 have a positive result. what is the positive predictive value of the new test? a575/(575+150) b. 600/(600+ 150) c. 575/(575+125) d. 600/(600+ 125)
Answers: 2
HURRRY TIMDE LIMIT Tasha used the pattern in the table to find the value of 4 Superscript negative 4...
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