Work out the equation of the line which has a gradient of 1/2 and passes through the point (4,-2) ❗️THIS IS DUE PRETTY SOON SO HELP IS APPRECIATED !!!❗️

The equation 2y = x - 8 is the equation of the line which has gradient, 1/2 and passes through the point (4,-2).

While working out the equation of a line;

This therefore forms a basis for working out the equation of a line as follows;

gradient/slope = (y - y1)/(x - x1)

Therefore;

By cross product, we have;

The equation of the line is therefore, 2y = x - 8.

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When slope and 1 point are known:

m = (1/2) x = 4 and y = -2

We first calculate "b"

b = y -mx

b = -2 -.5 * 4

b = -2 -2

b = -4

Then, we enter the value of "b" and the slope into this equation:

y = mx + b

y = .5x -4

Source: https://1728.org/distance.htm

Step-by-step explanation:

this doesn't make sense lol

their is no graph showing

step-by-step explanation: