Find the value or expression for 0...
sin(55)=cos(0)

t = -35 + 360n where n is any integer

Step-by-step explanation:

I assume o is theta.  I am going to use t for theta.

sin(55) = cos(t)

The easiest way is to know that one graph is a vertical shift of the other.  so sine starts at 0 while cosine starts at 1 and doesn't get to 0 until you are at an input of 45 (or pi/2 degrees).  so sin(x) = cos(x - 90) = cos(x + 270) and cos(x) = sin(x + 90) = sin(x - 270).  ALSO keep in mind you can add/ subtract an additional 360 since that cycles the graph again

Anyway, that is what you can use.

sin(55) = cos(t) = cos(55 - 90)

t = 55 - 90

t = -35

then again, remembering you can subtract a further 360 to get the same number the expression that is the answer is t = -35 + 360n where n is any integer

im pretty sure its

(8,15)

step-by-step explanation:

80 the answer is 80

step-by-step explanation: