Given that sin theta =21/29 what is the value of cos theta for 0 degrees < theta < 90 degrees

Cos θ = 20/29

Step-by-step explanation:

Given that,

Sin θ = 21/29

We know that,

Sin^2 θ + cos^2 θ = 1

Cos θ = √(1 - sin^2 θ)

= √(1 - 441/841)

= √ (841-441) /841

=√ (400/841)

= 20/29

Cos θ = 20/29

452,489 to the nearest thousand is 452,000

x= -3 and

step-by-step explanation:

to find the roots of a cubic, use division or factoring to find the factors then set equal to 0. as this is a difference of cubes, it factors into

where a is the cube root of .

here   this is 27 and the cube root of 27 is 3. so we write using the form:

.

set each factor to 0 and solve for x.

x-3=0

x=3

the quadratic expression does not factor and must be solved using the quadratic formula.

where a = 1, b=3, and c=9

this cubic has two complex roots.