Suppose a simple random sample of size n=1000 is obtained from a population whose size is nequals=1 comma 500 comma 0001,500,000 and whose population proportion with a specified characteristic is p equals 0.65 .p=0.65. complete parts (a) through (c) below.

Question

Suppose a simple random sample of size n = 1000 is obtained from a population whose size is N = 1,500,000 and whose population proportion with a specified characteristic is p = 0.65.

a. Describe the sampling distribution of  ^ p

b. What is the probability of obtaining x = 680 or more individuals with the characteristic?  P ( x ≥ 680 )  = _____  (Round to four decimal places as needed.)

a. The sampling distribution is

b. P ( x ≥ 680  = 0.0233

Step-by-step explanation:

Given

Sample Size, n = 1000

Population Size, N = 1500000

^ p  = 0.65

a.

To describe the sampling distribution of  ^ p , means to calculate the mean and the standard error of the sampling distribution (μ,σ)

From the question, we have

μp = P = 0.65

Calculating the standard error, σp

σp =

By Substitution

σp =

σp =

σp =

σp =

σp =

σp =

Hence, the sampling distribution is

b. Calculate P ( x ≥ 680 )

First, we need to determine the z-value

z = (^p - p)/σp

where ^p = 0.680, p = 0.65, σp = 0.0151

By Substitution

So, P ( x ≥ 680 ) = 1 - P(z<1.99)

From z table, P(z<1.99) = 0.9767

P ( x ≥ 680 ) = 1 - P(z<1.99) becomes

P ( x ≥ 680 ) = 1 - 0.9767

P ( x ≥ 680  = 0.0233

answer: the answer is one of

step-by-step explanation:   we are given to write a proper fraction where the whole is divided into an even number of equal parts less than ten, and an odd number of those parts exist.

an even number less than 10 may be one of 2, 4, 6 or 8. so, the whole may be one of these four evens.

now, an odd number of these parts must exist, so the numerator must be an odd number, one of 1, 3, 5 or 7. it cannot be 9 because then the fraction will become improper.

thus, our fraction may be one of the following

3030 ur welcome

step-by-step explanation: